• The essence of all Computation generically defined

    From olcott@polcott333@gmail.com to comp.theory,comp.ai.philosophy,comp.software-eng,sci.logic,sci.math on Fri Jan 16 16:58:20 2026
    From Newsgroup: sci.logic

    On 1/16/2026 4:21 PM, dart200 wrote:
    On 1/16/26 8:46 AM, Richard Damon wrote:
    On 1/16/26 4:08 AM, dart200 wrote:
    On 1/15/26 7:28 PM, Richard Damon wrote:
    On 1/15/26 7:23 AM, dart200 wrote:

    bro stick a giant dildo up ur asshole u hypocritical fuckface...

    when i tried to suggest improvements to the computational model,
    like RTMs, u then told me i *can't* do that because muh ct-thesis,
    and here u are crying about how no superior method has been found
    as if u'd ever even tried to look past the ct-thesis...

    No, you didn't suggest improvements to the model, you just showed
    you don't knoww what that means.

    You don't get to change what a "computation" is, that isn't part of
    the "model".

    you honestly could have just said that cause the rest of this is just
    u repeating urself as if that makes it more correct


    But I HAVE said it that simply, and you rejected it as you think you
    get to,

    but repeating urself doesn't make it more true




    The model would be the format of the machine, and while your RTM
    might be a type of machine that could be thought of, they don't do
    COMPUTATIONS, as it violates the basic rules of what a compuation IS.

    Computations are specific algorithms acting on just the input data.

    A fundamental property needed to reach at least Turing Complete
    ability, is the ability to cascade algorithms.

    Your RTM break that capability, and thus become less than Turing
    Complete.

    i'm sorry, RTMs are literally just TMs with one added instruction
    that dumps static meta-data + copies tape ... how have they *lost*
    power with that??? clearly they can express anything that TMs can ...

    Which means you don't understand how "TM"s work, as they don't have
    that sort of "instructions".

    fuck dude sorry "operation" is the term turing used, i added to the list
    of possible operations with RTMs, my god dude...

    see how fucking unhelpful u are???




    And, any algorithm that actually USES their capability to detect if
    they have been nested will become incorrect as a decider, as a
    decider is a machine that computes a specific mapping of its input
    to its output, and if that result changes in the submachine, only
    one of the answers it gives (as a stand-alone, or as the sub-
    machine) can be right, so you just show that it gave a wrong answer.

    u have proof that doesn't work yet you keep asserting this is the
    "one true way". seems like u just enjoy shooting urself in the foot,
    with the only actual rational way being it's just the "one true way"

    IT IS DEFINITION. Something you don't seem to understand.

    "Computation" is NOT defined by what some machine does, that is
    algorithms and results. "Computation" is the mapping generated by it,
    which MUST be a specific mapping of input to output.

    no one has defined "computation" well enough to prove that turing
    machines can compute them all,


    *The essence of all Computation generically defined*

    Computation only applies finite string
    transformation rules to finite string inputs.

    Computable functions are Computations that
    always stop running.

    The empty string counts as a string.
    --
    Copyright 2026 Olcott<br><br>

    My 28 year goal has been to make <br>
    "true on the basis of meaning expressed in language"<br>
    reliably computable.<br><br>

    This required establishing a new foundation<br>
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  • From Richard Damon@Richard@Damon-Family.org to comp.theory,comp.ai.philosophy,comp.software-eng,sci.logic,sci.math on Fri Jan 16 18:21:05 2026
    From Newsgroup: sci.logic

    On 1/16/26 5:58 PM, olcott wrote:
    On 1/16/2026 4:21 PM, dart200 wrote:
    On 1/16/26 8:46 AM, Richard Damon wrote:
    On 1/16/26 4:08 AM, dart200 wrote:
    On 1/15/26 7:28 PM, Richard Damon wrote:
    On 1/15/26 7:23 AM, dart200 wrote:

    bro stick a giant dildo up ur asshole u hypocritical fuckface...

    when i tried to suggest improvements to the computational model,
    like RTMs, u then told me i *can't* do that because muh ct-thesis, >>>>>> and here u are crying about how no superior method has been found >>>>>> as if u'd ever even tried to look past the ct-thesis...

    No, you didn't suggest improvements to the model, you just showed
    you don't knoww what that means.

    You don't get to change what a "computation" is, that isn't part of >>>>> the "model".

    you honestly could have just said that cause the rest of this is
    just u repeating urself as if that makes it more correct


    But I HAVE said it that simply, and you rejected it as you think you
    get to,

    but repeating urself doesn't make it more true




    The model would be the format of the machine, and while your RTM
    might be a type of machine that could be thought of, they don't do
    COMPUTATIONS, as it violates the basic rules of what a compuation IS. >>>>>
    Computations are specific algorithms acting on just the input data.

    A fundamental property needed to reach at least Turing Complete
    ability, is the ability to cascade algorithms.

    Your RTM break that capability, and thus become less than Turing
    Complete.

    i'm sorry, RTMs are literally just TMs with one added instruction
    that dumps static meta-data + copies tape ... how have they *lost*
    power with that??? clearly they can express anything that TMs can ...

    Which means you don't understand how "TM"s work, as they don't have
    that sort of "instructions".

    fuck dude sorry "operation" is the term turing used, i added to the
    list of possible operations with RTMs, my god dude...

    see how fucking unhelpful u are???




    And, any algorithm that actually USES their capability to detect if >>>>> they have been nested will become incorrect as a decider, as a
    decider is a machine that computes a specific mapping of its input
    to its output, and if that result changes in the submachine, only
    one of the answers it gives (as a stand-alone, or as the sub-
    machine) can be right, so you just show that it gave a wrong answer.

    u have proof that doesn't work yet you keep asserting this is the
    "one true way". seems like u just enjoy shooting urself in the foot,
    with the only actual rational way being it's just the "one true way"

    IT IS DEFINITION. Something you don't seem to understand.

    "Computation" is NOT defined by what some machine does, that is
    algorithms and results. "Computation" is the mapping generated by it,
    which MUST be a specific mapping of input to output.

    no one has defined "computation" well enough to prove that turing
    machines can compute them all,


    *The essence of all Computation generically defined*

    Computation only applies finite string
    transformation rules to finite string inputs.

    Computable functions are Computations that
    always stop running.

    The empty string counts as a string.


    In other words, you admit to not knowing what you are talking about.

    Note, that Computable Functions are a subset of the category Function,
    which are MAPPINGS of input to output (not something a computing machine
    does, that is a meaning in a different field of Computer Science)

    No "algorithm" needed to define a function, and it doesn't run in "steps"

    Computable Functions are Functions for which there exists a proper
    finite algorithm that can compute them for all values.

    It is that finite algorithm that needs to stop, not the "function" as functions don't run at all, they just are.

    You have had the told to you many times, but you don't care that you are
    just repeating your lies. as "facts" aren't important to you, as is
    seems words are flexible in meaning and you just redefine them as you
    want, which means everything you say is actually meaningless, as your
    words no longer have established meaning.
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